(9*10^-12)=(0.05+2x)*2*(x)

Solution for (9*10^-12)=(0.05+2x)*2*(x) equation:

(9*10^-12)=(0.05+2x)*2(x)

We move all terms to the left:

(9*10^-12)-((0.05+2x)*2(x))=0

We add all the numbers together, and all the variables

-((2x+0.05)*2x)+(9*10^-12)=0

We add all the numbers together, and all the variables

-((2x+0.05)*2x)-12+9.0E=0


We calculate terms in parentheses: -((2x+0.05)*2x), so:

(2x+0.05)*2x

We multiply parentheses

4x^2+0.1x

Back to the equation:

-(4x^2+0.1x)


We add all the numbers together, and all the variables

-(4x^2+0.1x)+12.4645364561=0

We get rid of parentheses

-4x^2-0.1x+12.4645364561=0

a = -4; b = -0.1; c = +12.4645364561;
Δ = b2-4ac
Δ = -0.12-4·(-4)·12.4645364561
Δ = 199.442583298
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{199.442583298}}{2*-4}=\frac{0.1-\sqrt{199.442583298}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{199.442583298}}{2*-4}=\frac{0.1+\sqrt{199.442583298}}{-8}
$